A large pizza has a diameter of 12 inches. Which of the following is the area of the pizza in terms of pi ()?
A. 24 πi n2
B. 48 π in2
C. 18π in2
D. 36 π in2
Before finding the area of the pizza, we need to find the radius of the pizza.
Find radius of the pizza in terms of diameter
Next, find area of the pizza using the radius of 6 inches
Substituting r=6 in the equation of the area of a circle
Thus, the pizza has an area of 36 π in2.
Therefore, the Correct Answer is D.
More Questions on TEAS 7 Math
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Q #1: 3(3x+3)=8x+5 Solve the equation above for x. Which of the following is correct?
A. 1
B. 4
C. -1
D. -4
Answer Explanation
We use the order of operation to solve for the unknown value of x.
3(3x+3)=8x+5
Multiply 3 with each number in the brackets
(3*3x)+(3*3)=8x+5
9x+9=8x+5
Subtract 9 from both sides
9x+9-9=8x+5-9
9x=8x-4
Subtract 8x on both sides
9x-8x=8x-8x-4
x=-4
Thus, the unknown value of x is -4.
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Q #2: One gallon of cleaning solution requires 10 oz of ammonia. If the maintenance department needs 51 gallons of solution to clean all of the floors, how much ammonia is needed?
A. 510 gallons
B. 51 gallons
C. 510 oz
D. 51 oz
Answer Explanation
We use given information to find how much ammonia is need to make the specified solution.
We are told, one gallon of cleaning solution requires 10 oz of ammonia. Expressing this mathematically yields two options:
\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\) or \(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)
Now we find how much ammonia is needed using option two.
\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)
From the above equation, gallon of solution will cancel, and oz of ammonia is left.
Therefore, the solution will require 510 oz of ammonia.
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Q #3: When the marks of a science test are graphed, the distribution of markss is symmetric with the majority of weights centered around a single peak. Which of the following describes the shape of this distribution?
A. Uniform
B. Skewed right
C. Bell-shaped
D. Bimodal
Answer Explanation
In a bell-shaped curve, the data distribution is symmetric around a single peak. The centering of data around a single peak means the mean, mode and median of the test are all equal to each other.
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Q #4: The scatter plot below shows the relationship between the number of hours a student plays golf and the student’s class attendance. Which of the following types of correlation is shown on the scatter plot?
A. Positive
B. Positive and negative
C. No correlation
D. Negative
Answer Explanation
Scatter plots can depict three correlations: positive, negative and no correlation. A positive correlation scatter plot reveals that as one variable increases, the other variable also increases as shown below
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Q #5: A student performs the following estimations. 35+192 230 258+350 610 947+1032 1980 Based on these estimations, which of the following is the student’s estimate of 694+7618?
A. 8320
B. 8500
C. 8300
D. 8310
Answer Explanation
Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows
35+192
227258+350=608
947+1032=1979
From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.
694+7618=8312
We can approximate 8312 based on the provided choices is 8310.
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Q #6: Which of the following is the weight of the cargo in a truck if 2/3 of the cargo weighs 530 pounds (lb)?
A. 795 lb
B. 1030 lb
C. 1590 lb
D. 688 lb
Answer Explanation
The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.
Solve for value of p by cross products
Multiply both sides by 3/2 a reciprocal of 2/3
The truck carries a cargo weighing 795 lb.
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Q #7: Which of the following percentages is equivalent to the fraction below? 7/8
A. 875%
B. 0.875%
C. 8.75%
D. 87.5%
Answer Explanation
We are required to find the percent equivalent of the given fraction.
We multiply 7/8 by 100 to convert it to percent. You convert fraction to percent.
Thus 7/8 is equal to 87.5%.
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Q #8: A math teacher obtained the following scores from a class of 45 students. Which of the following is the best way to display the frequency of each day of the week? Test score 50-59 60-69 70-79 80-89 90-99 Number of students 10 4 9 20 2
A. Scatterplot
B. Pie graph
C. Line graph
D. Histogram
Answer Explanation
In order for the teacher to better visualize the test performance for his class, he needs to present the mark distribution in chart form. A better chart visualizer is the histogram, which will show the frequency of marks against range of test scores. A bar graph will not be used because the rectangles need to touch one another.
In a bar graph, the rectangles do not touch each other. Therefore, it will not be a good chart visualizer.
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Q #9: Which of the following is the equivalence in kg for 220 lb? (2.2 lb =1 kg)
A. 110 kg
B. 2.20 kg
C. 50 kg
D. 100 kg
Answer Explanation
We two conversions when asked to convert between kg and lb
And
We need kg equivalent of 220 lb, therefore we use option 1 and carry out the conversions as follows:
Thus, 100kg is equal to 220lb.
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Q #10: The data below represents students’ test scores. Which of the following is the median of the set data? 24, 35, 18, 19, 22, 35, 16, 12, 26, 12, 23
A. 18
B. 22
C. 23
D. 19
Answer Explanation
The median of a data set is found in two ways:
For an odd data set, the median fall in the (N+1)/2 th position.
For an even data set, the median is the average of the element in the (N/2)th and (N+1)/2 th positions.
To find the median of the given data set, we need to arrange the elements from the smallest to the largest as follows:
12, 12, 16, 18, 19, 22, 23, 24, 26, 35, 35
There are 11 elements in the data set. 11 is an odd number and the median fall in the (N+1)/2 th position.
Median =(11+1)/2=12/2=6 th position.
From the organized data, the element in the 6th position is 22, which is the required median for the data set.
