Lana has $90. She spends 70% of the money. She then invests the remaining amount and earns a profit of 60%. How much money does she now have?
A. $16.20
B. $84.20
C. $43.20
D. $27.00
We need to find the amount Lana left after spending and investing another.
Lana spends=70% of $90=70/100 * 90 = $63
Amount left after spending=$(90-63) = $27
Lana is left with $27, which she will invest and earns a profit of 60%.
Profit earned=60% of $27 = 60/100 * 27 = $16.20
Therefore, Lana will have $27 + $16.20 = $43.20
Therefore, the Correct Answer is C.
More Questions on TEAS 7 Math
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Q #1: Which of the following is the greatest value?
A. 74÷95
B. 7/8
C. 0.72
D. 74%
Answer Explanation
To solve this problem, we need to have all options in fraction form.
74
95 = 
7/8 = 3/8
0.72 = 72/100
74% = 74/100
Now, find the least common denominator of 95, 8, and 100. The least common denominator is 3800, which we multiply by each fraction as follows:
74/95*3800=2960
7/8*3800=3325
72/100*3800=2736
74/100*3800=2812
We can see that the fraction 7/8 is the greatest among the given options.
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Q #2: Which of the following is the length of the unknown leg of a right triangle that has one leg length of 13 feet and a hypotenuse of 25 feet? (Round to the nearest tenth.)
A. 32 feet
B. 8 feet
C. 21.4 feet
D. 24 feet
Answer Explanation
From the given data, we can draw the following triangle by letting the unknown length to be p.
We apply the Pythagoras theorem, the value of p:
The unknown length of the triangle is about 21.4 feet.
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Q #3: A class of 40 students has 18 boys and 22 girls. What is ratio of girls to boys in the class?
A. 11:9
B. 20:9
C. 9:11
D. 20:11
Answer Explanation
A ratio is of the form a : b but can also be converted to a fraction of the form a/b, where b is not equal to zero. Besides, to in ration means per in fraction form.
In the class of 40 students, 22 are girls and 18 are boys. Thus, the ratio of girls to boys becomes:
The above fraction can be reduced further since 2 is a common factor in both 22 and 18. Thus
In ratio form, girls: boys=11:9
Thus, the ratio of girls to boys in a class of 40 students is 11 to 9.
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Q #4: A couple dining at a restaurant receives a bill for $58.60. They wish to leave a 16% gratuity. Which of the following is the estimated gratuity?
A. $8.48
B. $6.40
C. $9.38
D. $7.00
Answer Explanation
In this problem, we need to find the amount of gratuity the couple will leave. The gratuity is 16% of the total bill. Before solving the problem, the following are terms and their meaning in percent problems:
- Is means equals
- Of means multiply
- What means unknown (variable)
If we let x be the amount of gratuity, then translating the given problem into a mathematical equation becomes:
Now we evaluate the above equation noting that of means multiply.
So, the value of x=9.376 and to the nearest cent, x=9.38
There, a couple will leave a gratuity of $9.38.
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Q #5: A recipe calls for 1.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?
A. 6.33 mL
B. 12.325 mL
C. 7.395 mL
D. 0.797 mL
Answer Explanation
We are asked to find mL equivalent in 1.5 teaspoons. To carry out the operations, we utilize dimensional analysis to solve this problem as follows.
Converting between teaspoon and mL uses the following conversions:
Or
Since we want to remain with mL, use the second option and proceed as follows.
Thus, 1.5 teaspoons is equal to 7.395 mL
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Q #6: 3(3x+3)=8x+5 Solve the equation above for x. Which of the following is correct?
A. 1
B. 4
C. -1
D. -4
Answer Explanation
We use the order of operation to solve for the unknown value of x.
3(3x+3)=8x+5
Multiply 3 with each number in the brackets
(3*3x)+(3*3)=8x+5
9x+9=8x+5
Subtract 9 from both sides
9x+9-9=8x+5-9
9x=8x-4
Subtract 8x on both sides
9x-8x=8x-8x-4
x=-4
Thus, the unknown value of x is -4.
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Q #7: When the marks of a science test are graphed, the distribution of markss is symmetric with the majority of weights centered around a single peak. Which of the following describes the shape of this distribution?
A. Uniform
B. Skewed right
C. Bell-shaped
D. Bimodal
Answer Explanation
In a bell-shaped curve, the data distribution is symmetric around a single peak. The centering of data around a single peak means the mean, mode and median of the test are all equal to each other.
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Q #8: Lana has $90. She spends 70% of the money. She then invests the remaining amount and earns a profit of 60%. How much money does she now have?
A. $16.20
B. $84.20
C. $43.20
D. $27.00
Answer Explanation
We need to find the amount Lana left after spending and investing another.
Lana spends=70% of $90=70/100 * 90 = $63
Amount left after spending=$(90-63) = $27
Lana is left with $27, which she will invest and earns a profit of 60%.
Profit earned=60% of $27 = 60/100 * 27 = $16.20
Therefore, Lana will have $27 + $16.20 = $43.20
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Q #9: If a box of 45 syringes costs $720.00, which of the following is the cost of five syringes?
A. $75.00
B. $66.00
C. $82.00
D. $80.00
Answer Explanation
From the cost of 45 syringes, we are required to find the cost of 5 syringes. We set up a proportion equation by letting the cost of 5 syringes to y. Besides, we let the cost to be numerator and number of syringes to be denominator as follows.
Solve the value of y by cross products
Divide both sides by 45
Therefore, 5 syringes will cost $80.00.
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Q #10: One gallon of cleaning solution requires 10 oz of ammonia. If the maintenance department needs 51 gallons of solution to clean all of the floors, how much ammonia is needed?
A. 510 gallons
B. 51 gallons
C. 510 oz
D. 51 oz
Answer Explanation
We use given information to find how much ammonia is need to make the specified solution.
We are told, one gallon of cleaning solution requires 10 oz of ammonia. Expressing this mathematically yields two options:
\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\) or \(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)
Now we find how much ammonia is needed using option two.
\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)
From the above equation, gallon of solution will cancel, and oz of ammonia is left.
Therefore, the solution will require 510 oz of ammonia.
