There are 900 students enrolled in four allied health programs at a local community college. The percent students in each program are displayed in the pie chart. Which of the following is the number of students enrolled in the Radiologic Technology program?
A. 162
B. 171
C. 378
D. 189
We use the percentages and number of students to find the number of students enrolled in the respiratory care program as in the pie chart. The total percent of the whole piec chart sums to 100%.
If we let x represent the number of students enrolled in the Radiologic Technology program, we can set a proportion equation with number of students on the numerator and percentages on the denominator.
\(\frac{x}{21\%}\ =\ \frac{900}{100\%} \)
Find the value of x by cross-products
\(x\ *\ 100\%\ =\ 900\ students * 21\%\)
Divide both sides of the equation by 100%
\(x= \frac{900\ students\ *\ 21\%}{100\%}\ =\ 189\ students\)
Thus, 189 students out of 900 students will enroll for a respiratory care program.
Therefore, the Correct Answer is D.
More Questions on TEAS 7 Math
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Q #1: Which of the following is an appropriate unit of measure to express the length of a book?
A. Decameters
B. Kilometers
C. Centimeters
D. Meters
Answer Explanation
Explanation: centimeters is the appropriate unit to measure the length of a book.
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Q #2: A recipe calls for 6.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL? (Use the conversion rates as provided)
A. 32.05 mL
B. 29.55 mL
C. 34.20 mL
D. 25.80 mL
Answer Explanation
Explanation:
We need to find the mL in 6.5 teaspoons from the given information.
If we let x represent the amount of vanilla in mL, and set a proportion equation with number of teaspoons as numerator and mL as denominator, then:
(frac{6.5}{x} = frac{1}{4.93})
Find the value of x by cross-products
6.5 * 4.93 = x
32.05 = x
Therefore, 6.5 teaspoons equal 32.05 mL.
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Q #3: ((frac{x}{y}) + rw = z) Solve for x in the equation above.
A. x=y(z-rw)
B. x=rw(y-z)
C. x=w(z+ry)
D. x=rwy-z
Answer Explanation
The question requires us we make x the subject of the formula.
First, we subtract rw to both sides of the equation
Multiply both sides by y
Thus, the formula for finding the value of x is y(z-rw).
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Q #4: A person weighed themselves at 120 lb. Three months later they weighed themselves at 160 lb. Which of the following is the percent of weight the person gained over 3 months? (Round to the nearest percent.)
A. 66%
B. 33%
C. 35%
D. 30%
Answer Explanation
We need to find the percent change in weight of a person. To find the percent change, follow the following steps:
- Find absolute change in weight
- Find relative change
- Find the percent change from relative change.
Absolute change is the difference between the final value and initial value. Our initial value is 120 lb and final value is 160 lb. Then,
Relative change is given by
Percent change is determined by
To the nearest whole number, the percent change is 33%.
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Q #5: -1/6, -0.7, -1.8, -7/6 Of the number listed above, which number is the greatest?
A. -1/6
B. -0.7
C. -7/6
D. -1.8
Answer Explanation
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Q #6: How many liters are there in 560 milliliters?
A. 5.6
B. 0.56
C. 56
D. 5600
Answer Explanation
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Q #7: Which of the following is the decimal equivalent of 3/8?
A. 375
B. 3.75
C. 37.5
D. 0.375
Answer Explanation
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Q #8: The data below represents students’ test scores. Which of the following is the median of the set data? 80, 76, 92, 96, 44, 86, 56, 93, 69
A. 86
B. 69
C. 44
D. 80
Answer Explanation
Explanation: the median of a data set is the element that is found on the middle position.
To find median, organize the given data from the smallest to largest.
44, 56, 69, 76, 80, 86, 92, 93, 96
Now, the number of elements in the date set is 9, which is an odd number. The median falls in the position
(N+1)/2=(9+1)/2=10/2=5.
The number that falls in the 5th position is 80. Thus, 80 is the median of the data.
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Q #9: Which of the following is the median of the date set below? 30, -5, 8, -20, 23
A. 8
B. 30
C. -20
D. -5
Answer Explanation
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Q #10: Which of the following is the weight of the cargo in a truck if 3/5 of the cargo weighs 615 pounds (lb)?
A. 1025 lb
B. 1320 lb
C. 1548 lb
D. 788 lb
Answer Explanation
In this problem, we assume the truck carry a whole cargo to carry. Thus, total weight is found by dividing 615 lb by 3/5. Thus,
We change the division sign to product and multiply 615 by reciprocal of 3/5. Then,
(615 * frac{5}{3} = 1025 lb)
The weight of the cargo in the truck will be 1025 lb.
