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A bucket can hold 2500 mL. How many L can the bucket hold?

A. 0.25 mL

B. 25 mL

C. 2.5 L

D. 250 L

Answer Explanation:

Explanation: We know that 1 L=1000 mL and to change between L and mL we use the following two options

Therefore, the Correct Answer is C.

More Questions on TEAS 7 Math

  • Q #1: Which of the following is the greatest value?

    A. 43÷55

    B. 5/7

    C. 0.729

    D. 73%

    Answer Explanation

    we are asked to find the largest value from the options given. To solve this problem, we need to convert all the given values into fraction. Then find the least common denominator for all fractions, which we will use to multiply each fraction and make a comparison.

    43÷55=43/55

    5/7

    0.729=729/1000

    73%=73/100

    Now, we need to find the least common denominator of 55, 7, 1000, and 100, which is 77000. We multiply each fraction by 77000 as follows:

    43/55*77000=60200

    5/7*77000=55000

    729/1000*77000=56133

    73/100*77000=56210

     

    From the calculated values, it can be noted that 43/55 is the greatest value among the given options.

     

  • Q #2: Jacob has $100. She spends 87% of the money. She then invests the remaining amount and earns a profit of 75%. How much money does she now have?  

    A. $13.00

    B. $87.00

    C. $22.75

    D. $9.75

    Answer Explanation

    We are needed to find the amount Jacob will be left with after spending and reinvesting the rest using the given information.

    Amount Jacob spends=87% of $100=87/100*100=$87

    Amount left to invest=$(100-87)=$13

    Jacob is left with $13, which she invests and earns a profit of 75%.

    Profit earned on invested amount=75% of $13=75/100*13=$9.75

    So, Jacob will have $13+$9.75=$22.75

  • Q #3: 3(2x+5)=11x+5 Solve the equation above for x. Which of the following is correct?

    A. 1

    B. 2

    C. -1

    D. -2

    Answer Explanation

    We follow the order operations to solve for the unknown value of x.

    3(2x+5)=11x+5

    Open the bracket on the LHS by multiplying each term by 3

    (3*2x)+(3*5)=11x+5

    6x+15=11x+5

    Subtract 15 from both sides

    6x+15-15=11x+5-15

    6x=11x-10

    Subtract 11x on both sides

    6x-11x=11x-11x-10

    -5x=-10

    Divide both sides by -5

    -5x/-5=-10/-5

    x= 2

    Thus, the value of unknown value of x is 2.