A patient's temperature was recorded in degrees Fahrenheit every hour for 8 hr. The temperatures in Fahrenheit were 99.0°, 99.2°, 98.7°, 99.3°, 99.7°, 98.6°, 100.0° and 99.0°. Which of the following is the median temperature?
A. 99.5°F
B. 99.1°F
C. 99.2°F
D. 99°F
The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:
98.6, 98.7, 99.0, 99.0, 99.2, 99.3, 99.7, 100.0
(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})
From the data set above, there are 8 temperature values. The median is the temperature value in the middle position, which falls between the (frac{n}{2} th) and ((frac{n}{2} + 1) th) position. Here N=8 and median is found as:
(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)
The element in the 4.5th position is the average of the 4th and 5th element.
(frac{99.0 + 99.2}{2} = 99.1)
Thus 99.1 is the median temperature.
Therefore, the Correct Answer is B.
More Questions on TEAS 7 Math
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Q #1: Simplify the expression below. Which of the following is correct? \(18x^5yz\ \div\ \ 6xyz^4\)
A. \(3x^4z^3\)
B. \(3x^4yz^3\)
C. \(\frac{(3x)^4}{z^3}\)
D. \(\frac{(3x^4)}{z^3}\)
Answer Explanation
We use the properties of exponent with the same base to solve for above expression.
Multiplication of exponents with same base, we add the exponents
Division of exponents with same base, we subtract the exponents
Using these two properties, we can solve the expression:
Now we use the following properties:
y0 =1, and
, thus
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Q #2: Using the numbers below, which of the following is the greatest? 4/3, 27/20, 1.369, 1.357
A. 1.369
B. 4/3
C. 27/20
D. 1.357
Answer Explanation
to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.
4/3=1.333
2720=1.35
Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value
1.333 the number in second decimal place value is 3
1.35 the number in third decimal place value is 5
1.369 the number in third decimal place value is 6
1.357 the number in third decimal place value is 5
However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:
1.35 is same as 1.350 and the number in the third-place value is 0
1.357 the number in the third-place value is 7
Now, 0 is less than 7, and thus 1.35 is less than 1.357
Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:
1.333, 1.35, 1.357, 1.369
Thus, the corresponding given numbers organized from the smallest to the largest become:
4/3, 27/20, 1.357, 1.369
The greatest value is 1.369
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Q #3: The graph below compares the age of car to its value. Which of the following is the age of the car when its value is $12,500?
A. Between 2 and 3 years
B. Less than 1 year
C. Greater than 3 years
D. Between 1 and 2 years
Answer Explanation
We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.
Now, let’s extrapolate in the following diagram
The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.
