A recipe calls for 5.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?

A. 10.2 mL

B. 12 mL

C. 7.43 mL

D. 27 mL

Answer Explanation:

We need to find how many mL are in 5.5 teaspoons. We are told that 1 teaspoon is about 4.93 mL, which we interpret as follows:

Since we are looking for mL, we use the second option.

Thus, 5.5 teaspoons can hold approximately 27 mL.

Therefore, the Correct Answer is D.

Q #1: A student performs the following estimations. 26+180210 115+391510 497+20242520 Based on these estimations, which of the following is the student’s estimate of 545+7501?

A. 8030

B. 8060

C. 8160

D. 8050

Answer Explanation

From the given estimations, we can find the exact sum after adding the given numbers and see the trend the student utilizes to find their estimates. The actual sum is as follows

26+180=206

115+391=506

497+2024=2521

From the above evaluation, the students round the exact sum to the nearest tens. So, in the problem we need to approximate 545+7501.

545+7501=8046

The exact sum is 8046 and the approximate value after rounding to the nearest tens is 8050.
Q #2: How many feet are in 9 yards?

A. 45 ft

B. 18 ft

C. 36 ft

D. 27 ft

Answer Explanation

The interconversion of yards to feet utilizes the relationship 1 yard =3 feet. Then, 9 yards to ft becomes

t

There, 9 yards is equal to 27 ft.
Q #3: One gallon of cleaning solution requires 6 oz of ammonia. If the maintenance department needs 230 gallons of solution to clean all of the floors, how much ammonia is needed?

A. 1380 gallons

B. 6900 gallons

C. 1380 oz

D. 1400 oz

Answer Explanation

from the given data, one gallon of cleaning solution requires 6 oz of ammonia. The mathematical expression of this statement can be expressed in two ways:

Or

The question requires we find the amount of ammonia needed to make 230 gallons of the solution. So, we use the second option and proceed as follows:

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 1380 oz of ammonia.