An athlete can run 6 miles in 51 minutes. At this rate, how many miles could the athlete run in 90 minutes?
A. 15 miles
B. 11.5 miles
C. 45 miles
D. 10.6 miles
Here, the athlete runs 6 miles in 51 minutes, which can be expressed as:
Now, in 90 minutes, the athlete will cover about
Therefore, the athlete runs about 10.6 miles in 90 minutes.
Therefore, the Correct Answer is D.
More Questions on TEAS 7 Math
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Q #1: Which of the following is the mean of the set data below? 30, 29, 28, 30, 24, 12, 26, 33, 25, 23
A. 30
B. 21
C. 27
D. 26
Answer Explanation
The mean is the total divided by the number of elements in the data set. From the given data set:
Total=30+29+28+30+24+12+26+33+25+23=260
Number of items, N=10
Mean=total/N=260/10=26
The mean is 26.
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Q #2: What is the area of a square that measures 3.1m on each side?
A. 12.4m2
B. 9.61m2
C. 6.2m2
D. 9.1m2
Answer Explanation
Here we are required to find the area of the square of sides 3.1 m. The square is a four-sided figure with each side equal and opposite sides making 90 degrees.
Area of the square =side*side
Side=3.1 m
Area of the square=3.1 m *3.1 m=9.61 m2
Note: 3.1 + 3.1 = 6.2 which is a wrong answer.
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Q #3: A patient's temperature was recorded in degrees Fahrenheit every hour for 8 hr. The temperatures in Fahrenheit were 99.0°, 99.2°, 98.7°, 99.3°, 99.7°, 98.6°, 100.0° and 99.0°. Which of the following is the median temperature?
A. 99.5°F
B. 99.1°F
C. 99.2°F
D. 99°F
Answer Explanation
The median temperature can be found by organizing the temperature values from the smallest to the largest value as follows:
98.6, 98.7, 99.0, 99.0, 99.2, 99.3, 99.7, 100.0
(for an even set of numbers, Median = frac{(frac{n}{2})th observation + (frac{n}{2} + 1) th observation}{2})
From the data set above, there are 8 temperature values. The median is the temperature value in the middle position, which falls between the (frac{n}{2} th) and ((frac{n}{2} + 1) th) position. Here N=8 and median is found as:
(frac{(frac{n}{2})th + (frac{n}{2} + 1) th}{2} = )(frac{(frac{8}{2})th + (frac{8}{2} + 1) th }{2} = 4.5th position)
The element in the 4.5th position is the average of the 4th and 5th element.
(frac{99.0 + 99.2}{2} = 99.1)
Thus 99.1 is the median temperature.
