/

An athlete runs 5 miles in 25 minutes and then changes their pace to run the next 3 miles in 15 minutes. Overall, what is the average time in minutes it takes the athlete to run 1 mile?

A. 7 minutes

B. 5 minutes

C. 6.5 minutes

D. 8.5 minutes

Answer Explanation:

to find the average time the athlete runs in 1 mile, find total time divided by total distance covered in the two runs.

Total distance=5+3=8 miles

Total time=25+15=40 minutes

We now know that the athlete runs 8 miles in 40 minutes, so the time the athlete will run in 1 mile will be:  

                          

In 5 minutes, the athlete runs 1 mile.

Therefore, the Correct Answer is B.

More Questions on TEAS 7 Math

  • Q #1: How many feet are in 9 yards?

    A. 45 ft

    B. 18 ft

    C. 36 ft

    D. 27 ft

    Answer Explanation

    The interconversion of yards to feet utilizes the relationship 1 yard =3 feet. Then, 9 yards to ft becomes

                                            t

    There, 9 yards is equal to 27 ft.

  • Q #2: One gallon of cleaning solution requires 6 oz of ammonia. If the maintenance department needs 230 gallons of solution to clean all of the floors, how much ammonia is needed?

    A. 1380 gallons

    B. 6900 gallons

    C. 1380 oz

    D. 1400 oz

    Answer Explanation

    from the given data, one gallon of cleaning solution requires 6 oz of ammonia. The mathematical expression of this statement can be expressed in two ways:

               

    Or

                   

    The question requires we find the amount of ammonia needed to make 230 gallons of the solution. So, we use the second option and proceed as follows:

                       

    From the above equation, gallon of solution will cancel, and oz of ammonia is left.

    Therefore, the solution will require 1380 oz of ammonia.

  • Q #3: A bucket can hold 2500 mL. How many L can the bucket hold?

    A. 0.25 mL

    B. 25 mL

    C. 2.5 L

    D. 250 L

    Answer Explanation

    Explanation: We know that 1 L=1000 mL and to change between L and mL we use the following two options