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How would you remove unreacted copper oxide from solution?

A. Filtration

B. Distillation

C. Evaporation

D. Decantation

Answer Explanation:

A) Filtration (Correct Answer): Filtration is a commonly used method to separate solid particles, such as unreacted copper oxide, from a liquid solution. The solution containing the dissolved copper sulfate can pass through the filter paper, while the solid copper oxide particles are retained on the filter.

B) Distillation: Distillation is a process used to separate components of a mixture based on differences in their boiling points. It is not typically used to separate solid particles from a liquid solution.

C) Evaporation: Evaporation involves heating the solution to allow the solvent (water) to vaporize, leaving behind the solute (copper sulfate) as solid crystals. While evaporation can concentrate the solution, it does not effectively remove solid particles like unreacted copper oxide.

D) Decantation: Decantation involves pouring off the liquid portion of a mixture, leaving the solid behind. While it can be used to separate solid and liquid phases, it may not effectively separate fine solid particles like unreacted copper oxide from the solution. Filtration would be a more suitable method for this purpose.

Therefore, the Correct Answer is A.

More Questions on TEAS 7 Science

  • Q #1: What ions make ammonia solution alkaline?

    A. Cl- ions

    B. H+ ions

    C. Na+ ions

    D. OH- ions

    Answer Explanation

    A) Cl- ions: Chloride ions (Cl-) are typically found in salts and do not contribute directly to the alkalinity of ammonia solution.

    B) H+ ions: Hydrogen ions (H+) typically characterize acidic solutions, not alkaline solutions. Ammonia solution doesn't contain H+ ions.

    C) Na+ ions: Sodium ions (Na+) are typically found in salts and do not contribute directly to the alkalinity of ammonia solution.

    D) OH- ions (Correct Answer): Ammonia solution becomes alkaline due to the presence of hydroxide ions (OH-). Ammonia (NH3) reacts with water to form ammonium ions (NH4+) and hydroxide ions (OH-), increasing the concentration of OH- ions and making the solution alkaline.

  • Q #2: Why is KOH a strong alkali?

    A. Because it reacts vigorously with acids

    B. Because it forms a basic solution when dissolved in water

    C. Because in solution it fully dissociates into K+ and OH-

    D. Because it forms insoluble precipitates with metal cations

    Answer Explanation

    A) Because it reacts vigorously with acids: While KOH does react with acids to form salts and water, the strength of an alkali is not solely determined by its reactivity with acids.

    B) Because it forms a basic solution when dissolved in water: This statement is true, but it does not fully explain why KOH is considered a strong alkali. Many compounds can form basic solutions when dissolved in water.

    C) Because in solution it fully dissociates into K+ and OH- (Correct Answer): KOH is considered a strong alkali because it fully dissociates in aqueous solution into potassium ions (K+) and hydroxide ions (OH-). This dissociation leads to a high concentration of hydroxide ions in solution, making it strongly alkaline.

    D) Because it forms insoluble precipitates with metal cations: This statement describes the formation of insoluble hydroxide precipitates when alkali solutions are added to solutions of metal salts. However, it does not fully explain why KOH itself is considered a strong alkali.

  • Q #3: What is the formula of ammonium sulfate?

    A. NH4SO4

    B. (NH4)2SO4

    C. (NH4)SO4

    D. (NH3)2SO4

    Answer Explanation

    A) NH4SO4: This formula suggests a compound where one ammonium ion is combined with one sulfate ion, which is not the correct composition of ammonium sulfate.

    B) (NH4)2SO4 (Correct Answer): This formula correctly represents ammonium sulfate, indicating that it consists of two ammonium ions (NH4+) and one sulfate ion (SO4^2-).

    C) (NH4)SO4: This formula suggests a compound with one ammonium ion combined with one sulfate ion, which is not the correct composition of ammonium sulfate.

    D) (NH3)2SO4: This formula suggests a compound where two ammonia molecules (NH3) are combined with one sulfate ion, which is incorrect. Ammonium sulfate contains ammonium ions (NH4+), not ammonia molecules (NH3).