Simplify the expression. Which of the following is correct?
A. 9
B. 8
C. 6
D. 20
We follow the order of operations to solve the given expression. The order of operations is PEMDAS:
- Parentheses
- Exponents
- Multiplication and Division (in order from left to right)
- Addition and Subtraction (in order from left to right)
First, we start with the numerator and solve it as follows
[3(6+5*4)]
We start with multiplication in parenthesis, 5*4=20. The expression becomes
[3(6+20)]
Then, we conduct the addition in parenthesis 6+20=26. Then, the expression becomes
[3(26)]=3*26=78
Now, we solve for denominator, which is 26/2=13.
Thus, the expression is reduced into
The expression reduces into 6.
Therefore, the Correct Answer is C.
More Questions on TEAS 7 Math
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Q #1: Which of the following is the median of the date set below? 3, -5, 9, -1, 0
A. 9
B. -5
C. -1
D. 0
Answer Explanation
The median of a data set is a number that falls in the middle of the data set. To find the median, the numbers in the data set are arranged from the smallest to the largest. In the given data set, the organized arrangement is:
-5, -1, 0, 3, 9
There are five elements in the data set, and the median falls in the third position from either side. Thus, 0 falls in the third position.
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Q #2: A bag contains six green balls, eight red balls, and three yellow balls. If one ball is randomly selected from the ball, which of the following is the probability that the ball is green?
A. 10/17
B. 3/17
C. 2/17
D. 6/17
Answer Explanation
The probability of finding a green ball is given by
Total number of balls in the bag=6+8+3=17 balls
Therefore, the probability of drawing a green ball from the bag containing 17 balls is 6/17.
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Q #3: Which of the following is the total number of whole boxes that measure 4 ft * 4 ft * 4 ft that can be stored in a room that measures 11.5 ft * 11.5 ft * 11.5 ft, if the size of the boxes cannot be altered?
A. 10
B. 24
C. 20
D. 18
Answer Explanation
The number of boxes is determined by volume of the room divided by volume of one box.
Number of boxes
Therefore, about 24 boxes can be stacked in the room.
