The graph below represents the amount of rainfall in a particular state by month. Which of the following is the total rainfall for the first 5 months of the year?
A. 11 inches
B. 7.5 inches
C. 4.5 inches
D. 3.5 inches
The first five months of the year are January, February, March, April, and May. We use to graph to find the amount of rainfall in each month as follows:
In the month of January, rainfall was between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches
On February, rainfall was 1 inch and on March the rainfall was 2 inches.
On April, the rainfall amount was 4 inches while on month of May, the rainfall was about 3.5 inches. Therefore, total rainfall in the first 5 months was:
Total rainfall=0.5 inches+1 inches+ 2 inches+4 inches + 3.5 inches =11 inches
Therefore, the Correct Answer is A.
More Questions on TEAS 7 Math
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Q #1: One gallon of cleaning solution requires 10 oz of ammonia. If the maintenance department needs 51 gallons of solution to clean all of the floors, how much ammonia is needed?
A. 510 gallons
B. 51 gallons
C. 510 oz
D. 51 oz
Answer Explanation
We use given information to find how much ammonia is need to make the specified solution.
We are told, one gallon of cleaning solution requires 10 oz of ammonia. Expressing this mathematically yields two options:
\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\) or \(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)
Now we find how much ammonia is needed using option two.
\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)
From the above equation, gallon of solution will cancel, and oz of ammonia is left.
Therefore, the solution will require 510 oz of ammonia.
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Q #2: A bucket can hold 5000 mL. How many L can the bucket hold?
A. 500L
B. 5L
C. 50L
D. 0.05L
Answer Explanation
To change between L and mL, the following two options are used.
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Q #3: Which of the following is the greatest value?
A. 74÷95
B. 7/8
C. 0.72
D. 74%
Answer Explanation
To solve this problem, we need to have all options in fraction form.
74
95 = 
7/8 = 3/8
0.72 = 72/100
74% = 74/100
Now, find the least common denominator of 95, 8, and 100. The least common denominator is 3800, which we multiply by each fraction as follows:
74/95*3800=2960
7/8*3800=3325
72/100*3800=2736
74/100*3800=2812
We can see that the fraction 7/8 is the greatest among the given options.
