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The Life Cycle of HIV Which of the following allows the AIDS virus, which contains RNA, to insert viral DNA into the DNA of a host T-cell after the AIDS virus enters the cell?

A. Receptor proteins located on the surface of the virus

B. The protein that makes up the capsid of the virus

C. Reverse transcriptase, an enzyme encoded by the virus

D. The phospholipids found on the envelope of the virus

Answer Explanation:

The AIDS virus (HIV virus) is Class VI or Group VI in the Baltimore Classification. Based on the Baltimore Classification, this specifically involves the reverse transcriptase enzyme and it is encoded by the virus.

This is the enzyme that will produce DNA molecules from the viral RNA. This is the mechanism involved where it will use the reverse transcriptase enzyme to insert viral DNA into the genetic material of the host cell.

Therefore, the Correct Answer is C.

More Questions on TEAS 7 Science

  • Q #1: Which of the following vessels carries oxygenated blood?

    A. Inferior vena cava

    B. Pulmonary vein

    C. Pulmonary artery

    D. Superior vena cava

    Answer Explanation

    Pulmonary vein carries oxygenated blood from the lungs to the heart. Pulmonary artery carries deoxygenated blood from the heart to the lungs.
    Superior and inferior vena cava bring in deoxygenated blood from all other parts of the body to the heart.

  • Q #2: Base your answer on the graph and on your knowledge of biology. Which is a true statement about the relationship between pH and enzyme action?

    A. All enzymes work best at a neutral pH.

    B. Adding more acid does not affect the rate of activity of an enzyme.

    C. Enzymes function only in a pH range of 4.0 to 5.5.

    D. The activity of an enzyme is affected by pH.

    Answer Explanation

  • Q #3: An atom of lead (Pb) has a mass number of 207. How many neutrons are in the nucleus?

    A. 130

    B. 125

    C. 82

    D. 84

    Answer Explanation

    We find the number of neutrons as follows

    Number of neutrons

                = mass number – atomic number

                = 207 – 82

                = 125 neutrons