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Which of the following is the appropriate unit of a measure to express the weight of a mobile phone?

A. Liter

B. Milliliter

C. Gram

D. Milligram

Answer Explanation:

Here, we are required to find the unit of measuring mass. The SI unit of mass is kilogram but other derived units are grams, milligrams, microgram and more.

A kilogram is a large quantity for measuring heavier objects but grams can used to measure small and light objects such as the mass of the mobile phone. Therefore, gram is the appropriate unit for measuring weight of a mobile phone.

Therefore, the Correct Answer is C.

More Questions on TEAS 7 Math

  • Q #1: Which of the following is the decimal form of 98.2%?

    A. 9.82

    B. 9820

    C. 982

    D. 0.982

    Answer Explanation

    Percentages are fractions with denominator equal to 100. To convert a percent to decimal form, divide the value by 100.

    The decimal form of 98.2% is 0.982.

  • Q #2: As the dollar rate increases in a day, the amount of investment, stock prices, and forex exchange deposit available also decreases. Which of the following is the independent variable?

    A. Amount of investment

    B. Dollar rate

    C. Stock prices

    D. Forex exchange deposit

    Answer Explanation

    Based on the given scenario, the outcome of measuring the daily dollar rate is the decline in investment, stock prices, and forex exchange. The three outcomes are dependent variables while the dollar rate is the independent variable.

  • Q #3: A bucket containing 2 2/5 gallons of water is 4/7 full. How many gallons of water is in one fully filled bucket?

    A. 4 1/5

    B. 2 1/5

    C. 4 4/5

    D. 2 2/5

    Answer Explanation

    we are asked to find the number of gallons a full tank can hold. A full tank is equivalent to 1.

    Convert the mixed fraction into proper fraction as follows

    (2frac{2}{5}=frac{left(2ast5 ight)+2}{5}=frac{10+2}{5}=frac{12}{5})

    If we let x be the number of gallons in full tank, and setting up the proportion equation with the number of gallons on the numerator and fraction of tank on denominator as follows.

    (frac{x gallons}{1 full tank}=frac{frac{12}{5} gallons}{frac{4}{7}full tank})

    Cross-multiply to find the value of x.

    (frac{x }{1 full tank}=frac{frac{12}{5} gallons}{frac{4}{7}full tank})

    (x astfrac{4}{7}full tank=frac{12}{5} gallonsast1 full tank)

    (x =frac{frac{12}{5} gallonsast1 full tank}{frac{4}{7}full tank}=frac{12}{5}divfrac{4}{7} gallons=frac{12}{5}astfrac{7}{4}gallons=frac{21}{5}gallons)

    Converting 21/5 to a mixed fraction is 4 1/5. Thus, when the tank is full, it holds 4 1/5 gallons of water.