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Which of the following values is the greatest?

A. 3/8

B. 6.25

C. 10/7

D. 7.4

Answer Explanation:

To find the greatest number from the given options, convert the decimal numbers into fractions.

6.25 becomes 625/100

7.4 becomes 74/10

The LCM for the denominators of 8, 100, 7, and 10 is 2800. Now we can multiply each fraction with the LCM.

3/8*2800=1050

625/100*2800=17500

10/7*2800=4000

74/10*2800=20720

The fraction 7.4 is the greatest of all.

Therefore, the Correct Answer is D.

More Questions on TEAS 7 Math

  • Q #1: Solve for w in the equation below.

    A. w=rxy+z

    B. w=(x/ry)+(z/r)

    C. w=y(z+rx)

    D. w=(x/ry)-(z/r)

    Answer Explanation

     We are asked to make w the subject of the formula.

    First, we rearrange the equation by to ensure w is on the right hand of the equation.

    Then, divide both sides by r

    Multiply both sides by y

    The above equation can be rearranged into

    Thus, the formula for finding the value of w is (x/ry)-(z/r).

  • Q #2: How many milliliters are there in 3.9 liters?

    A. 390

    B. 0.39

    C. 3, 900

    D. 39

    Answer Explanation

     we use the relation 1 L=1000 mL to convert 3.9 L to mL as follows.

    Thus, 3.9 L is 3900 mL.

  • Q #3: Soft Drinks Orange Two 24-packs for $15; one 24-pack for $9 Root Beer One 24-pack for $14 Cream Soda One 12-pack for $3 A consumer needs to purchase at least 50 soft drinks for a picnic. Which of the following combinations is the most cost-effective?

    A. 2 two-24 packs of Orange and 1 pack of Cream Soda

    B. 3 one 24-pack of Orange

    C. 2 packs of Root Beer and 1 pack of Cream Soda

    D. 5 packs of cream Soda

    Answer Explanation

    To find the cheapest option, we find the expenditure on each given option.:

    2 two-24 packs of Orange and 1 pack of Cream Soda=2($15)+$3=$33

    3 one 24-pack of Orange=3($9)=$27

    2 packs of Root Beer and 1 pack of Cream Soda=2($14)+$3=$31

    5 packs of cream Soda=5($3)=$15

    Spending 5 packs of cream soda is the cost-effective option.